Last updated at Aug. 25, 2021 by Teachoo

Transcript

Ex 2.2, 2 Find p(0), p(1) and p(2) for each of the following polynomials: (i) p(y) = y2 – y + 1 Given p(y) = y2 – y + 1 Putting y = 0 p(0) = (0)2 – 0 + 1 = 0 – 0 + 1 = 1 Putting y = 1 p(1) = (1)2 – 1 + 1 = 1 – 1 + 1 = 1 Putting y = 2 p(2) = (2)2 – 2 + 1 = 4 – 2 + 1 = 3

Ex 2.2

Ex 2.2,1
Important

Ex 2.2, 2 (i) You are here

Ex 2.2, 2 (ii)

Ex 2.2, 2 (iii)

Ex 2.2, 2 (iv)

Ex 2.2, 3 (i)

Ex 2.2, 3 (ii)

Ex 2.2, 3 (iii) Important

Ex 2.2, 3 (iv)

Ex 2.2, 3 (v)

Ex 2.2, 3 (vi)

Ex 2.2, 3 (vii) Important

Ex 2.2, 3 (viii)

Ex 2.2, 4 (i)

Ex 2.2, 4 (ii)

Ex 2.2, 4 (iii) Important

Ex 2.2, 4 (iv)

Ex 2.2, 4 (v)

Ex 2.2, 4 (vi) Important

Ex 2.2, 4 (vii)

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.